JESSICA CARVALHO
NPI 1780565192
Psychologist - Addiction (Substance Use Disorder) in Orefield, PA

NPI Status: Active since September 11, 2025

Contact Information

2970 CORPORATE CT
OREFIELD, PA
ZIP 18069
Phone: (610) 481-0444

NPI Profile Information
Primary Taxonomy
NPI Validation
Other Providers Same Location
Frequently Asked Questions

Individual
Female
Psychologist
Addiction (Substance Use Disorder)

About JESSICA CARVALHO

This page provides the complete NPI Profile along with additional information for Jessica Carvalho, a provider established in Orefield, Pennsylvania with a medical specialization in Psychologist, focusing in addiction (substance use disorder) . The healthcare provider is registered in the NPI registry with number 1780565192 assigned on September 2025. The practitioner's primary taxonomy code is 103TA0400X. The provider is registered as an individual and her NPI record was last updated one year ago.

NPI: 1780565192
Provider Name: JESSICA CARVALHO
Gender: Female
Entity Type: Individual
Location Address: 2970 CORPORATE CT OREFIELD, PA 18069
Location Phone: (610) 481-0444
Mailing Address: 144 E MARKET ST BETHLEHEM, PA 18018
Is Sole Proprietor?: No
Enumeration Date: 09-11-2025
Last Update Date: 09-11-2025
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Specialty - Primary Taxonomy

The NPI enumerator requires providers to submit at least one taxonomy code. A taxonomy code is a unique 10-character code that describes the healthcare provider type, classification, and the area of specialization. There could be only one primary taxonomy code per NPI record. For individual NPIs the license data is associated to the taxonomy code.

Classification: Psychologist Addiction (Substance Use Disorder)
Taxonomy Code: 103TA0400X
Type: Behavioral Health & Social Service Providers
Taxonomy Description: A psychologist with a proficiency that involves the application of psychological treatment of addiction stemming from the use of alcohol and other psychoactive substances (e.g., nicotine, marijuana, cocaine, heroin) or behavioral addictions (e.g., gambling) with the aim of cessation or reduction of use and/or the amelioration of emotional, behavioral, interpersonal and other problems arising from the addictive behavior.

NPI NPI Number Validation

How NPI Validation Works

The NPI validation process uses the ISO-standard Luhn algorithm, a mathematical "handshake", to ensure that a provider's 10-digit ID is authentic and free of common typing errors.

To verify the NPI 1780565192, we treat the final digit (2) as the Check Digit—the target answer we need to reach. The process begins by taking the first nine digits and adding a constant value of 24, which accounts for the "80840" prefix required for all U.S. health identifiers. We then double every other digit starting from the right and sum the individual digits of those results together. For this specific NPI, that total comes to 58. The final step is to find the difference between that total and the next multiple of ten (60 - 58 = 2).

Digit-by-digit view

Use the first nine digits for the calculation. Starting from the right, double every other digit. The last digit is the check digit and is not part of the calculation.

Pos 1

Doubled → 2

Pos 2

Unchanged

Pos 3

Doubled → 16 → 1 + 6

Pos 4

Unchanged

Pos 5

Doubled → 10 → 1 + 0

Pos 6

Unchanged

Pos 7

Doubled → 10 → 1 + 0

Pos 8

Unchanged

Pos 9

Doubled → 18 → 1 + 8

Check

Target digit

Regular digit Doubled digit Check digit

Step 1: Double every other digit from the right

Starting with the rightmost digit of the first nine digits, double every other value. If doubling creates a two-digit number, add those digits together.

1 → 2 8 → 16 → 7 5 → 10 → 1 5 → 10 → 1 9 → 18 → 9

Step 2: Add all digits plus the NPI constant

Add the transformed values, the unchanged digits, and the constant 24.

2 + 7 + 1 + 6 + 0 + 1 + 0 + 6 + 1 + 0 + 1 + 1 + 8 + 24 = 58

Step 3: Find the amount needed to reach the next multiple of 10

The next multiple of ten after 58 is 60. The difference is the calculated check digit.

60 - 58 = 2

This NPI is valid

The calculated check digit is 2, which matches the last digit of 1780565192.