JANINA LANDON
NPI 1306506928
Licensed Psychiatric Technician in San Luis Obispo, CA

NPI Status: Active since December 22, 2021

Contact Information

2180 JOHNSON AVE
SAN LUIS OBISPO, CA
ZIP 93401
Phone: (805) 461-6048

NPI Profile Information
Primary Taxonomy
NPI Validation
Other Providers Same Location
Frequently Asked Questions

Individual
Female
Licensed Psychiatric Technician

About JANINA LANDON

This page provides the complete NPI Profile along with additional information for Janina Landon, a provider established in San Luis Obispo, California with a medical specialization in Licensed Psychiatric Technician. The healthcare provider is registered in the NPI registry with number 1306506928 assigned on December 2021. The practitioner's primary taxonomy code is 167G00000X with license number PT35073 (CA). The provider is registered as an individual and her NPI record was last updated 4 years ago.

NPI: 1306506928
Provider Name: JANINA LANDON
Gender: Female
Entity Type: Individual
Location Address: 2180 JOHNSON AVE SAN LUIS OBISPO, CA 93401
Location Phone: (805) 461-6048
Mailing Address: 2180 JOHNSON AVE SAN LUIS OBISPO, CA 93401
Is Sole Proprietor?: No
Enumeration Date: 12-22-2021
Last Update Date: 12-22-2021
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Specialty - Primary Taxonomy

The NPI enumerator requires providers to submit at least one taxonomy code. A taxonomy code is a unique 10-character code that describes the healthcare provider type, classification, and the area of specialization. There could be only one primary taxonomy code per NPI record. For individual NPIs the license data is associated to the taxonomy code.

Classification: Licensed Psychiatric Technician
Taxonomy Code: 167G00000X
Type: Nursing Service Providers
License No.: PT35073
License State: CA
Taxonomy Description: An individual licensed by the state board as a Psychiatric Technician based upon completion of a prescribed course of theory and clinical practice, with two thirds of the clinical practice time focused on mental and developmental disorders. The psychiatric technician practices under the direct supervision of a physician, psychologist, registered nurse or other professional to provide care to patients with mental disorders and developmental disabilities.

NPI NPI Number Validation

How NPI Validation Works

The NPI validation process uses the ISO-standard Luhn algorithm, a mathematical "handshake", to ensure that a provider's 10-digit ID is authentic and free of common typing errors.

To verify the NPI 1306506928, we treat the final digit (8) as the Check Digit—the target answer we need to reach. The process begins by taking the first nine digits and adding a constant value of 24, which accounts for the "80840" prefix required for all U.S. health identifiers. We then double every other digit starting from the right and sum the individual digits of those results together. For this specific NPI, that total comes to 52. The final step is to find the difference between that total and the next multiple of ten (60 - 52 = 8).

Digit-by-digit view

Use the first nine digits for the calculation. Starting from the right, double every other digit. The last digit is the check digit and is not part of the calculation.

Pos 1

Doubled → 2

Pos 2

Unchanged

Pos 3

Doubled → 0

Pos 4

Unchanged

Pos 5

Doubled → 10 → 1 + 0

Pos 6

Unchanged

Pos 7

Doubled → 12 → 1 + 2

Pos 8

Unchanged

Pos 9

Doubled → 4

Check

Target digit

Regular digit Doubled digit Check digit

Step 1: Double every other digit from the right

Starting with the rightmost digit of the first nine digits, double every other value. If doubling creates a two-digit number, add those digits together.

1 → 2 0 → 0 5 → 10 → 1 6 → 12 → 3 2 → 4

Step 2: Add all digits plus the NPI constant

Add the transformed values, the unchanged digits, and the constant 24.

2 + 3 + 0 + 6 + 1 + 0 + 0 + 1 + 2 + 9 + 4 + 24 = 52

Step 3: Find the amount needed to reach the next multiple of 10

The next multiple of ten after 52 is 60. The difference is the calculated check digit.

60 - 52 = 8

This NPI is valid

The calculated check digit is 8, which matches the last digit of 1306506928.